Indices Rules Worksheets, Questions and Revision (2024)

Rules of Indices Revision

Indices Rules

Indices Rules builds on the 7 rules from Powers and Roots. We will cover 3 more complicated rules here. Make sure you are confident with the following topics before moving onto laws and indices.

  • Collecting like terms
  • Powers and roots

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Indices Rule 8: Fractional Powers

The fractional indices laws apply when the power is a fraction.

\textcolor{red}{a}^{\large{\frac{\textcolor{blue}{b}}{\textcolor{limegreen}{c}}}} = \sqrt[\textcolor{limegreen}{c}]{\textcolor{red}{a}^\textcolor{blue}{b}}

This is commonly use to show square and cube roots.

\textcolor{red}{x}^{\large{\frac{\textcolor{limegreen}{1}}{\textcolor{blue}{2}}}}= \sqrt[\textcolor{blue}{2}]{\textcolor{red}{x}^\textcolor{limegreen}{1}} =\sqrt[\textcolor{blue}{2}]{\textcolor{red}{x}}

\textcolor{red}{x}^{\large{\frac{\textcolor{limegreen}{1}}{\textcolor{blue}{3}}}}= \sqrt[\textcolor{blue}{3}]{\textcolor{red}{x}^\textcolor{limegreen}{1}} =\sqrt[\textcolor{blue}{3}]{\textcolor{red}{x}}

Note: it doesn’t matter which order you carry out the square root and multiplication operations. In other words, the rule can also be written as

\textcolor{red}{a}^{\large{\frac{\textcolor{blue}{b}}{\textcolor{limegreen}{c}}}} = (\sqrt[\textcolor{limegreen}{c}]{\textcolor{red}{a}})^\textcolor{blue}{b}

You should try to carry out the operations in the order that makes the calculation as simple as possible.

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Indices Rules Worksheets, Questions and Revision (1)

Indices Rules Worksheets, Questions and Revision (2)

Indices Rules Worksheets, Questions and Revision (3)

Your 2024 Revision Partner

@mmerevise

Open TikTok

Indices Rule 9: Multi-step Fractional Powers

You may also be asked to simplify expressions where the numerator is not \bf{1}.

\textcolor{red}{64}^{\large{\frac{\textcolor{limegreen}{2}}{\textcolor{blue}{3}}}}= \sqrt[\textcolor{blue}{3}]{\textcolor{red}{64}^\textcolor{limegreen}{2}}

\sqrt[\textcolor{blue}{3}]{\textcolor{red}{64}} = \textcolor{red}{4}

\textcolor{red}{4}^\textcolor{limegreen}{2} = \textcolor{red}{16}

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Level 4-5GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Indices Rule 10: Negative Powers

Negative powers flip the fraction and put 1 over the number

In general, the result of a negative power is “\bf{1} over that number to the positive power”, i.e.

\textcolor{red}{a}^{-\textcolor{limegreen}{b}} = \dfrac{1}{\textcolor{red}{a}^\textcolor{limegreen}{b}}

for any value of a or b.When the power is \textcolor{blue}{-1}, this takes the form,

\textcolor{red}{a}^{\textcolor{blue}{-1}}=\dfrac{1}{\textcolor{red}{a}} or \textcolor{red}{10}^{\textcolor{blue}{-1}} = \dfrac{1}{\textcolor{red}{10}}

When the number is a fraction, the negative power flips the fraction.

\bigg(\dfrac{\textcolor{blue}{a}}{\textcolor{limegreen}{b}}\bigg)^{-\textcolor{red}{x}} = \bigg(\dfrac{\textcolor{limegreen}{b}}{\textcolor{blue}{a}}\bigg)^\textcolor{red}{x}

Level 4-5GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Level 4-5GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Example 1: Negative Powers

Simplify the following, 4^{-3}.

[2 marks]

We now know that 4^{-3} is equal to \dfrac{1}{4^3}. We also know that

4^3=4\times 4\times 4=16\times 4=64.

So, we get that

4^{-3}=\frac{1}{64}.

Level 4-5GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Example 2: Fractional Powers and Roots

Simplify the following, 9^{\frac{3}{2}}.

[2 marks]

So, we know that 9^{\frac{3}{2}} is equal to \sqrt[2]{9^3} or (\sqrt[2]{9})^3.

So, to work out (\sqrt[2]{9})^3, we first have to square root 9, which is easy enough – the square root of 9 is 3. So, (\sqrt[2]{9})^3 becomes 3^3, which is

3^3=3\times 3\times 3 = 27

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Example 3: Multiplication and Powers

Write 2^{15}\times 8^{-4} as a power of 2, and hence evaluate the expression. (Non calculator)

[3 marks]

The first part of the expression is a power of 2, whilst the second part is a power of 8.

we know that

8 = 2^3

This means we can rewrite the following,

8^{-4}=\left(2^3\right)^{-4}

Next, using Rule 3, we can simplify,

\left(2^3\right)^{-4}=2^{3\times(-4)}=2^{-12}

So the whole expression can be written as

2^{15}\times2^{-12},

Finally using Rule 1we simplify the expression further.

2^{15}\times2^{-12}=2^{15+(-12)}=2^3

Thus, we have written the expression as a power of 2. Evaluating this final answer gives

2^3 = 8

Level 6-7GCSEAQAEdexcelOCRWJECCambridge iGCSEEdexcel iGCSE

Rules of Indices Example Questions

So, we can’t use any laws straight away since the terms don’t have the same base. However, if we recognise that 9=3^2, then we can write the first term as

\left(3^2\right)^5

Using the power law, we get

\left(3^2\right)^5=3^{2\times5}=3^{10}

Therefore, the whole expression becomes

3^{10}\times3^{-5}

Applying the multiplication law, this simplifies to

3^{10+(-5)}=3^5

Thus, we have written the expression as a power of 3.

Indices Rules Worksheets, Questions and Revision (4)

Save your answers with

Indices Rules Worksheets, Questions and Revision (5)

Gold Standard Education

Sign Up Now

Firstly, as 3^2=9, the inverse operation gives, \sqrt{9}=3

So, that leaves 6^{-2}, this becomes the following fraction,

6^{-2}=\dfrac{1}{6^2}

We know that 6^2=6\times 6=36, so

6^{-2}=\dfrac{1}{36}

Multiplying our two answers together, we get

\sqrt{9}\times 6^{-2}=3\times\dfrac{1}{36}=\dfrac{3}{36}=\dfrac{1}{12}

Indices Rules Worksheets, Questions and Revision (6)

Save your answers with

Indices Rules Worksheets, Questions and Revision (7)

Gold Standard Education

Sign Up Now

This expression can be rewritten as,

\sqrt4 \times (\sqrt4)^3

Given we know that \sqrt4=2 , this becomes,

2\times2^3

Hence,

2\times2^3=2\times8=16

Notice that in this example we chose to perform the \sqrt{4} operation before cubing the answer. We could alternatively write the expression as \sqrt{4^3}, but in this case the first option is easier.

Indices Rules Worksheets, Questions and Revision (8)

Save your answers with

Indices Rules Worksheets, Questions and Revision (9)

Gold Standard Education

Sign Up Now

As it is a negative power we can rewrite this as,

8^{-\frac{5}{3}}=\frac{1}{8^{\frac{5}{3}}}

Now, we can work out the denominator, which we will write as,

8^{\frac{5}{3}}=\sqrt[3]{8^5}=(\sqrt[3]{8})^5

We know that \sqrt[3]{8}=2. So this simplifies to,

(\sqrt[3]{8})^5=2^5

Counting up in powers of 2: 4, 8, 16, 32 – we see that 32 is the 5th power of 2, so

\sqrt[3]{8}^5=32

Therefore, the answer is,

8^{-\frac{5}{3}}=\dfrac{1}{32}

Indices Rules Worksheets, Questions and Revision (10)

Save your answers with

Indices Rules Worksheets, Questions and Revision (11)

Gold Standard Education

Sign Up Now

Rules of Indices Worksheet and Example Questions

Indices Rules Worksheets, Questions and Revision (12)

(NEW) Rules of Indices Exam Style Questions - MME

Level 6-7GCSENewOfficial MME

Exam QuestionsMark Scheme

Rules of Indices Drill Questions

Indices Rules Worksheets, Questions and Revision (13)

Indices Rules - Drill Questions

Level 4-5GCSE

Exam Questions

Indices Rules Worksheets, Questions and Revision (14)

Fractional And Negative Indices - Drill Questions

Level 6-7GCSE

Exam Questions

Indices Rules Worksheets, Questions and Revision (15)

Rules of Indices - Drill Questions

Level 6-7GCSE

Exam QuestionsMark Scheme

Indices Rules Worksheets, Questions and Revision (2024)
Top Articles
Latest Posts
Article information

Author: Edmund Hettinger DC

Last Updated:

Views: 5896

Rating: 4.8 / 5 (78 voted)

Reviews: 85% of readers found this page helpful

Author information

Name: Edmund Hettinger DC

Birthday: 1994-08-17

Address: 2033 Gerhold Pine, Port Jocelyn, VA 12101-5654

Phone: +8524399971620

Job: Central Manufacturing Supervisor

Hobby: Jogging, Metalworking, Tai chi, Shopping, Puzzles, Rock climbing, Crocheting

Introduction: My name is Edmund Hettinger DC, I am a adventurous, colorful, gifted, determined, precious, open, colorful person who loves writing and wants to share my knowledge and understanding with you.